Answer
The girl was $1.07\text{ m}$ above the water.
Work Step by Step
We know that
$y=v_{\circ}sin\theta t-\frac{1}{2}gt^2$
We plug in the known values to obtain:
$y=(2.25m/s)sin 35^{\circ}(0.616s)-(0.5)(9.81m/s^2)(0.61s)^2$
$y=-1.07m$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 106: 43
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
