Answer
The vertical component is: $$v_{vf}=-(11.0\text{ m/s})\hat{\bf\space y}.$$
The landing angle is $-37.5^\circ$.
Work Step by Step
We know that
$v_y=v_ysin\theta$
We plug in the known values to obtain:
$v_y=(18m/s)(sin 37.5^{\circ})$
$v_y=10.96m/s$
