Answer
$\textbf{(a)}$
$$v_h=14.3\text{ m/s}.$$
$\textbf{(b)}$
$$t_f=2.23\text{ s}.$$
Work Step by Step
(a) We know that
$v_{\circ x}=v_{\circ} cos\theta$
We plug in the known values to obtain:
$v_{\circ x}=(18m/s)(cos37.5^{\circ})$
$v_{\circ x}=14.3m/s$
(b) We know that
$t=\frac{2v_{\circ}sin\theta}{g}$
We plug in the known values to obtain:
$t=\frac{(2)(18m/s)(sin 37.5^{\circ})}{9.8m/s^2}$
$t=2.23s$
