Answer
$-53.1^{\circ}, 40.3m$
Work Step by Step
We know that
$2\vec A+\vec B=2(12.1m)\hat x+(-32.2m)\hat y=(24.2m)\hat x+(-32.2m)\hat y$
Now the direction is given as
$\theta=tan^{-1}(\frac{-32.2}{24.2})=-53.1^{\circ}$
and the magnitude is given as
$|2\vec A+\vec B|=\sqrt{(24.2)^2+(-32.2)^2}=40.3m$