Answer
The dog has traveled 11 m when the owners meet.
Work Step by Step
The owners each walk 5.0 m. Time required for the owners to meet each other:
$time$ $elapsed=\frac{distance}{average speed}=\frac{5.0m}{1.3m/s}=3.8s$.
The distance traveled by the dog:
Distance = (average speed)(time elapsed) $=$
$=(3.0m/s)(3.8s)=11m$.
