Answer
(a) $Average$ $speed=9.934\times10^{-2}m/s$
(b) $Average$ $speed=0.2222mi/h$
Work Step by Step
$10months=(10 months)(\frac{30days}{1month})(\frac{24h}{1day})=7200h$
$7200h=(7200h)(\frac{3600s}{1h})=2.592\times10^{7}s$
$1600 mi = (1600mi)(\frac{5280ft}{1mi})(\frac{1m}{3.281ft})=2.575\times10^{6}m$
(a) $Average$ $speed=\frac{distance}{time elapsed}=\frac{2.575\times10^{6}}{2.592\times10^{7}}=9.934\times10^{-2}m/s$
(b) $Average$ $speed=\frac{distance}{time elapsed}=\frac{1600mi}{7200h}=0.2222mi/h$