Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 27 - Early Quantum Theory and Models of the Atom - Problems - Page 800: 39

Answer

$4.7\times10^{-12}m$

Work Step by Step

We find the wavelength using equation 27–8. The neutron is not relativistic. $$\lambda=\frac{h}{p}=\frac{h}{mv}$$ $$\lambda=\frac{6.63\times10^{-34}J \cdot s }{(1.67\times10^{-27}kg)(8.5\times10^4m/s)}$$ $$=4.7\times10^{-12}m$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.