Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 9 - Rotational Dynamics - Problems - Page 248: 72

Answer

$x=0.7m$

Work Step by Step

Let's choose the axis of rotation to be at the support on the right. - The plank's weight $W_1=225N$ produces a counterclockwise (positive) torque. Because the plank is uniform, center of gravity is at the midpoint $2.5m$ from each end, so the lever arm is $2.5-1.1=1.4m$ - The person's weight $W_2=450N$ produces a clockwise (negative) torque. The lever arm is $x$ Because the system is in equilibrium, $$\sum\tau=1.4W_1-xW_2=0$$ $$x=\frac{1.4W_1}{W_2}=0.7m$$
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