Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 9 - Rotational Dynamics - Problems - Page 248: 61

Answer

The person's mass is $28kg$

Work Step by Step

When the person stands at a distance of $R_1=1.5m$ from the center, the total moment of inertia is $$I_1=I_{carousel}+m_{person}R_1^2=125+2.25m$$ When the person stands at a distance of $R_2=0.75m$ from the center, the total moment of inertia is $$I_2=I_{carousel}+m_{person}R_2^2=125+0.56m$$ Angular momentum is conserved, so $$I_1\omega_1=I_2\omega_2$$ $$(125+2.25m)0.6=(125+0.56m)0.8$$ $$75+1.35m=100+0.45m$$ $$0.9m=25$$ $$m=28kg$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.