Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 140: 56

Answer

The speed the chamber must move is $33.2m/s$

Work Step by Step

We have $r=15m$ and $a_c=7.5g=73.5m/s^2$ The speed required to reach that amount of acceleration is $$v^2=ar$$ $$v=\sqrt{ar}=33.2m/s$$
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