Answer
At 6 o'clock position, $T=17.96N$
At 12 o'clock position, $T=14.04N$
Work Step by Step
The stick tension is in fact the normal force acted on the ball: $T=F_N$
At 3'o clock position, only the tension provides the centripetal force: $F_c=T=16N$
At 6'o clock position, the tension opposes the ball's weight, therefore, $$F_c=T-mg$$ $$T=F_c+mg=16+0.2\times9.8=17.96N$$
At 12'o clock position, the tension support the ball's weight to provide for $F_c$, therefore, $$F_c=T+mg$$ $$T=F_c-mg=16-0.2\times9.8=14.04N$$
