Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 140: 44

Answer

$v=17.3m/s$

Work Step by Step

When the rider is sitting stationary on the seat, there is no net force exerted upon the driver, and therefore, the normal force and the rider's weight balance each other. In other words, $W=F_N=770N$ At the top of the loop, normal force and the weight support each other to give centripetal force. The sensor records $F_N=350N$ here. $$F_c=W+F_N=770+350=1120N$$ $$\frac{mv^2}{r}=1120$$ $$v=\sqrt{\frac{1120r}{m}}$$ We know $r=21m$. The rider's mass can be found by $m=W/9.8=78.57kg$ $$v=17.3m/s$$
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