Answer
6.9 m/$s^{2}$
Work Step by Step
period = 0.4 $\times$ 4 = 1.60 s
v = $\frac{distance}{time}$
= $\frac{2 \times π \times 0.45}{1.60}$
$\approx$ 1.77 m/s
a = $\frac{v^{2}}{r}$
= $\frac{1.77^{2}}{0.45}$
$\approx$ 6.9 m/$s^{2}$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 138: 7
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