Answer
$a=4.1m/s^2$
Work Step by Step
The arch has a diameter of $5cm$, so its radius $r=2.5cm=0.025m$
Blood's speed $v=0.32m/s$
Therefore, the magnitude of the blood's centripetal acceleration is $$a=\frac{v^2}{r}=4.1m/s^2$$
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 138: 6
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