Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 117: 86

Answer

$P_{min}=400N$

Work Step by Step

Let's examine the forces deciding whether the small cubes slide downward or not: - Its weight $mg=4\times9.8=39.2N$, which forces the cube to slide down. - Static friction $f_s=\mu_s F_N=0.71F_N$, which opposes the downward movement. To be able to keep the cube from sliding, these forces at least need to balance each other. $$f_s=0.71F_N=39.2N$$ $$F_N^{min}=55.2N$$ $F_N$ here is the horizontal force that causes the cube's acceleration: $$F_N=ma$$ $$a_{min}=\frac{55.2}{4}=13.8m/s^2$$ Now, to find $P$, we consider the whole system. It has acceleration $a=13.8m/s^2$ and its total weight $M=4+25=29kg$. Thus, $$P_{min}=Ma=400N$$
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