Answer
(a) $T=914.27N$
(b) $T=822N$
Work Step by Step
$W_{man}=822N$
The tension in the cable $T$ and the weight of the man $W_{man}$ act in opposite directions. Here, we take the upward motion of $T$ to be positive. Therefore, $$\sum F=T-W_{man}$$
(a) The man is given an upward acceleration $a=+1.1m/s^2$. From Newton's 2nd Law, $$\sum F=T-W_{man}=m_{man}a$$ $$T=W+\frac{W}{g}a=822+\frac{822}{9.8}\times1.1=914.27N$$
(b) The man is pulled at a constant velocity, meaning $\sum F=0$. Therefore, $$T=W_{man}=822N$$
