Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 51: 66

Answer

The graph is drawn in the image, V = 2.7 m/s

Work Step by Step

Please see the attached image first. The velocity is the slope of a position-versus-time graph. Since the object’s velocity is constant and it moves in the +x direction, the graph will be a straight line with a positive slope, beginning at x = −16 m when t = 0 s. At t = 18 s, we can get the position should be x = −16 m + 48 m = +32 m. The position-versus time graph for the motion is given in the image. The velocity of the object = slope of the graph = $\frac{32\space m -(-16\space m)}{18\space s -0}=2.7\space m/s$
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