Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 2 - Kinematics in One Dimension - Problems - Page 51: 74

Answer

$$109m$$

Work Step by Step

Since el-Guerrouj has run the mile in less time than the time Roger takes to run the same distance, el-Guerrouj will win the race. We find: $$ D=v_{a v g .} t_{G} $$ Where $v_{a r g}$ is the average velocity for Roger and $t_{G}$ is the time that el-Guerrouj takes to finish the mile; thus: $$ \frac{(1609 \mathrm{m})}{t_{R}} t_{G}=D $$ We are told that $t_{G}=3: 43.13=3 \times 60+43.13=223.13 \mathrm{s}$ , $t_{R}=3: 59.4=3 \times 60+59.4=239.4 \mathrm{s},$ so: $$ \begin{aligned} &\frac{(1609 \mathrm{m})}{(239.4 \mathrm{s})}(223.13 \mathrm{s})=D \\ &=1500 \mathrm{m} \end{aligned} $$ This is the distance that Roger runs when el-Guerrouj runs the mile, thus el-Guerrouj would have won by: $$ 109 \mathrm{m}=(1609 \mathrm{m})-(1500 \mathrm{m}) $$
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