Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 11 - Fluids - Problems - Page 308: 8

Answer

$\textbf{Ans)}$ $ Volume_{can} =2.2963\times 10^{-5}$ $m^{3}$

Work Step by Step

The density of an Object in terms of mass and volume is given as $$M=ρ× Volume$$ The total Mass of Full black cherry soda is 0.416 kg. $M_T = M_{can} +M_{soda}$ $0.416 = M_{can} +M_{soda}$ But $$M_{soda}=ρ_{soda}× Volume_{soda}$$ $M_{soda} = 1000\times 3.54\times10^{-4}$ $M_{soda} = \text{0.354 kg}$ $0.416 - \text{0.354 } = M_{can} $ $M_{can} = \text{0.062 kg}$ Now, $$M_{can}=ρ_{can}× Volume_{can}$$ $ Volume_{can} = \frac{0.062}{2700}$ $m^{3}$ $\textbf{Ans)}$ $ Volume_{can} =2.2963\times 10^{-5}$ $m^{3}$
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