Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems - Page 277: 43

Answer

The time it takes for the ball to attain greatest speed is $0.4s$

Work Step by Step

In a simple pendulum, $$\frac{2\pi}{T}=\sqrt{\frac{g}{L}}$$ $$T=\frac{2\pi}{\sqrt{\frac{g}{L}}}=2\pi\sqrt{\frac{L}{g}}$$ Here, the string's length $L=0.65m$, so the motion's period is $$T=1.62s$$ The ball attains greatest speed at the bottom point of the motion. Since 1 revolution finishes when the ball goes up to its original position, going to the bottom point of the motion is $1/4$ revolution, taking $1/4$ time of the motion's period $T$. Therefore, the time it takes for the ball to attain greatest speed is $$\frac{T}{4}=0.4s$$
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