Answer
0.240 m
Work Step by Step
s = ut + 0.5a$t^{2}$
4 = 0 + 0.5a$(0.75)^{2}$
a = 14.2 m/$s^{2}$
Net force = ma
= 7(14.2)
= 99.6 N
F = k$\Delta$x
415($\Delta$x) = 99.6
$\Delta$x $\approx$ 0.240 m
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