Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 1 - Introduction and Mathematical Concepts - Problems - Page 24: 65

Answer

$(a)\space B=10.4\space units$ $(b)\space C=12\space units$

Work Step by Step

Let's take due north to be the direction of the +y, and due east to be the direction of the +x. The components of the resultant C are A and B. The angle that C makes with the x-axis is then $\theta=tan^{-1}(\frac{B}{A})$ (a) $B=Atan\theta=6\times tan60^{\circ}= 10.4\space units$ (b) $|C|=\sqrt {A^{2}+B^{2}}=\sqrt {(6)^{2}+(10.4)^{2}}=12\space units$
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