Answer
The kinetic energy of each pellet is $~~250~J$
Work Step by Step
We can find the kinetic energy of each pellet:
$K = \frac{1}{2}~m~v^2$
$K = \frac{1}{2}~(0.0020~kg)(500~m/s)^2$
$K = 250~J$
The kinetic energy of each pellet is $~~250~J$.
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 255: 112b
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