Answer
The magnitude of the momentum of each pellet is $~~1.0~kg~m/s$
Work Step by Step
We can find the magnitude of the momentum of each pellet:
$p = m~v$
$p = (0.0020~kg)(500~m/s)$
$p = 1.0~kg~m/s$
The magnitude of the momentum of each pellet is $~~1.0~kg~m/s$.