Answer
The speed of the spring gun is $~~4.4~m/s$
Work Step by Step
We can use conservation of momentum to find the speed $v_f$ of the spring gun:
$p_f = p_i$
$(240~g+60~g)~v_f = (60~g)(22~m/s)$
$v_f = \frac{(60~g)(22~m/s)}{300~g}$
$v_f = 4.4~m/s$
The speed of the spring gun is $~~4.4~m/s$