Answer
The average force on the ball from the player's foot is $~~3000~N$
Work Step by Step
In part (a), we found that the impulse on the ball due to the kick is $~~9.0~kg~m/s$
We can find the average force:
$F~t = J$
$F = \frac{J}{t}$
$F = \frac{9.0~kg~m/s}{3.0\times 10^{-3}~s}$
$F = 3000~N$
The average force on the ball from the player's foot is $~~3000~N$.
