Answer
The 40-kg skater moves a distance of $~~6.2~m$
Work Step by Step
Let the 40-kg skater be at the origin and let the 65-kg skater be at the x-coordinate $x = 10~m$
We can find the center of mass:
$x_{com} = \frac{(40~kg)(0)+(65~kg)(10~m)}{40~kg+65~kg} = 6.2~m$
Since the two skaters will meet at the center of mass, the 40-kg skater moves a distance of $~~6.2~m$.
