Answer
$P = 1300~W$
Work Step by Step
We can find the rate of change of kinetic energy:
$P = F~v$
$P = m~a~v$
$P = (15~kg)(2.0~m/s^2)(30~m/s)$
$P = 900~W$
We can find the rate of change of gravitational potential energy:
$P = \frac{dU}{dt}$
$P = \frac{d}{dt}~(mgh)$
$P = \frac{d}{dt}~(mgd~sin~\theta)$
$P = mgv~sin~\theta$
$P = (15~kg)(9.8~m/s^2)(30~m/s)~(sin~5.0^{\circ})$
$P = 380~W$
We can find the total power:
$P = 900~W+380~W = 1300~W$
