Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 213: 135b

Answer

The average power is $~~860~W$

Work Step by Step

In part (a), we found that the change in mechanical energy is $~~8600~J$ We can find the time it takes the block to increase its speed to $30~m/s$: $v_f = v_0+at$ $t = \frac{v_f - v_0}{a}$ $t = \frac{30~m/s - 10~m/s}{2.0~m/s^2}$ $t = 10~s$ We can find the average power: $P = \frac{8600~J}{10~s} = 860~W$ The average power is $~~860~W$
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