Answer
$5.5\times 10^6\ N$
Work Step by Step
Given that:
The maximum power of the Luxery liner $P=92\ MW = 92\times 10^6 \ W$
The speed of the object $v =32.5\ knots$
Then, we convert given speed to m/s:
1 knot =$1.852\ km/h$
So $32.5\ knots = 32.5\times 1.852\ km/h = 60.19\ km/h$
1 km = 1000 m and 1 hour = 3600 seconds
So $60.19\ km/h = 60.19\times \frac{1000\ m}{3600\ s}=16.71\ m/s$
Therefore, Force exerted on the ship is $F =\frac{P}{v}$;
$F =\frac{92\times 10^{6}\ W}{16.7\ m/s} = 5.5\times 10^6\ N$
