Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 44 - Quarks, Leptons, and the Big Bang - Problems - Page 1365: 43c

Answer

The Earth's new period of revolution would be $~~247~years$

Work Step by Step

In part (a), we found that the orbital speed would be $v = 121~m/s$ We can find the Earth's new period of revolution: $T = \frac{2\pi~r}{v}$ $T = \frac{(2\pi)~(1.5\times 10^{11}~m)}{121~m/s}$ $T = 7.79\times 10^9~s$ $T = (7.79\times 10^9~s)[\frac{1~year}{(365)(24)(3600~s)}]$ $T = 247~years$ The Earth's new period of revolution would be $~~247~years$
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