Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 44 - Quarks, Leptons, and the Big Bang - Problems - Page 1365: 43b

Answer

The ratio of this orbital speed to the Earth's present orbital speed is $~~0.00406$

Work Step by Step

In part (a), we found that the orbital speed would be $v = 121~m/s$ We can find the ratio of this orbital speed to the Earth's present orbital speed: $\frac{121~m/s}{29,800~m/s} = 0.00406$ The ratio of this orbital speed to the Earth's present orbital speed is $~~0.00406$
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