Answer
The answer is $ 1.90\times \hspace{2mm}10^{-18}$ kg m/s.
We use the conversion: $1$MeV = $1.6\times \hspace{2mm}10^{13}$ J
We begin with these things:
Work Step by Step
The final steps are:
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 44 - Quarks, Leptons, and the Big Bang - Problems - Page 1363: 8a
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