Answer
The $A_2^+$ particle is a boson.
Work Step by Step
$A_2^+ \rightarrow \rho^0+\pi^+$
$A_2^+ \rightarrow \pi^+ + \pi^- +\pi^+$
On the right side of this process, there are three spin-zero mesons.
According to the conservation law, $A_2^+$ also has spin zero.
Therefore, the $A_2^+$ particle is a boson.
