Answer
The $L_\mu$ conservation law is violated.
The charge conservation law is violated.
Work Step by Step
The $\mu^-$ has $L_{\mu} = +1$
The $e^+$ has $L_{\mu} = 0$
The $\nu_e$ has $L_{\mu} = 0$
The $\bar{\nu_{\mu}}$ has $L_{\mu} = -1$
Therefore, the $L_\mu$ conservation law is violated.
The $\mu^-$ has charge $-1$
The $e^+$ has charge $+1$
The $\nu_e$ has charge $0$
The $\bar{\nu_{\mu}}$ has charge $0$
Therefore, the charge conservation law is violated.
