Answer
$^{244}Pu$ decays into $^{240}U$ ($Z = 92$)
Work Step by Step
$^{244}Pu$ has 94 protons.
Since $^{244}Pu$ has 244 nucleons, then $^{244}Pu$ has 150 neutrons.
An alpha particle consists of 2 protons and 2 neutrons.
If $^{244}Pu$ emits an alpha particle, the resulting particle has 92 protons and 240 nucleons.
$^{244}Pu$ decays into $^{240}U$ where $Z = 92$
