Answer
Since $^{196}Pt$ is stable, further decays do not occur.
Work Step by Step
After the electron is emitted, one neutron will decay into a proton.
Thus, the number of neutrons decreases by 1 and the number of protons increases by 1.
It is transformed into $^{196}Pt$
Since $^{196}Pt$ is stable, further decays do not occur.
