Answer
$E_{B} = 28.35 MeV$
Work Step by Step
The binding energy of $\alpha $ particle is
$E_{B} = \Delta E_1 - \Delta E_2 $
$E_{B} = (-24.1 MeV) - 4.25 MeV$
$E_{B} = 28.35 MeV$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 42 - Nuclear Physics - Problems - Page 1304: 48c
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
