Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1302: 8b

Answer

The percentage deviation is $~~0.032~\%$

Work Step by Step

We can find the percentage deviation: $\frac{M_{app}-M}{M}~\times 100\%$ $= \frac{A~m_p-1.007 825~u}{1.007 825~u}~\times 100\%$ $= \frac{(1)(1.673\times 10^{-27}~kg)-(1.007 825)(1.660538782\times 10^{-27}~kg)}{(1.007 825)(1.660538782\times 10^{-27}~kg)}~\times 100\%$ $= 0.032~\%$ The percentage deviation is $~~0.032~\%$
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