Answer
$\Delta_n = 8.1~MeV/c^2$
Work Step by Step
We can find the mass excess of a neutron:
$\Delta_n = M - A$
$\Delta_n = 1.008665~u - 1~u$
$\Delta_n = 0.008665~u$
We can express this mass excess in units of $MeV/c^2$:
$\Delta_n = 0.008665~u$
$\Delta_n = (0.008665)~(1.66053886\times 10^{-27}~kg)(\frac{1~MeV}{1.6\times 10^{-13}~J})[\frac{(3.0\times 10^8~m/s)^2}{c^2}]$
$\Delta_n = 8.1~MeV/c^2$
