Answer
The intensity of the light does not determine whether or not an electron is ejected.
Work Step by Step
We can state the photoelectric equation:
$hf = K_{max}+ \Phi$
$\Phi$ is the work function and it is a property of the target material. If energy is transferred from a photon to an electron such that $hf \gt \Phi$, then the electron can escape from the material.
The frequency of an individual photon determines whether or not an electron is ejected, but the intensity of the light does not.
