Answer
For a given frequency of incident light, the value of $K_{max}$ is higher for potassium than for sodium.
Work Step by Step
$K_{max} = e~V_{stop}$
For a given frequency, the value of $V_{stop}$ is higher for potassium than for sodium.
Therefore, for a given frequency of incident light, the value of $K_{max}$ is higher for potassium than for sodium.
