Answer
For the same mass of explosive, the ratio of the energy released in a nuclear explosion to that released in a TNT explosion is $~~6.0\times 10^6$
Work Step by Step
In part (a), we found that $3.0~kg$ of fissionable material releases $2.7\times 10^{14}~J$ of energy.
We can find the energy released by $3.0~kg$ of TNT:
$E = (\frac{3.0~kg}{0.227~kg/mol})(3.4\times 10^6~J) = 4.5\times 10^7~J$
We can find the ratio of the energy released:
$\frac{2.7\times 10^{14}~J}{4.5\times 10^7~J} = 6.0\times 10^6$
For the same mass of explosive, the ratio of the energy released in a nuclear explosion to that released in a TNT explosion is $~~6.0\times 10^6$
