Answer
$\Delta E=2.7\times 10^{14}J$
Work Step by Step
We know that;
$\Delta E=\Delta m c^2$
We plug in the known values to obtain:
$\Delta E=3.00\times 0.0010\times (2.8\times 10^8)^2=2.7\times 10^{14}J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 37 - Relativity - Problems - Page 1151: 86a
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