Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1111: 32b

Answer

There is no minimum.

Work Step by Step

First, we can use the given frequency, $f=1.0*10^3Hz$, and the speed of sound in water, $v=1450m/s$, to find the wavelength. $\lambda = v / f$ $\lambda = (1450m/s) / (25*10^3Hz)$ $\lambda =1.45m$ Now we can use the given diameter, $d=0.60m$, in equation (36-12), to find the required value of $\sin \theta$ $\sin \theta= 1.22 \frac{\lambda}{d}$ $\sin \theta= 1.22 \frac{1.45m}{0.60m}$ $\sin \theta= 2.9$ We require the value of $\sin \theta $ to be 2.9, but since the value of $\sin \theta$ can't be greater than 1, there is no minimum.
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