Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1111: 29b

Answer

$8.4*10^{7}km$

Work Step by Step

We are given a length of 10 light years, so $L=10ly$, or in meters, we have $L=9.46*10^{16}m$. We can use right triangle trigonometry we found in part a ($\theta_R= 8.8*10^{-7}rad$) to find the distance between the stars, d. $\sin \theta = d/L$ $d=L\sin \theta $ $d=9.46*10^{16}m*\sin 8.8*10^{-7}rad$ $d= 8.4*10^{10}m$ $d= 8.4*10^{7}km$
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