Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 35 - Interference - Problems - Page 1079: 91a

Answer

$\theta_2 = 22.0^{\circ}$

Work Step by Step

We can find $\theta_2$: $\frac{1}{3.0}~sin~\theta_2 = \frac{1}{4.0}~sin~\theta_1$ $sin~\theta_2 = \frac{3.0}{4.0}~sin~\theta_1$ $sin~\theta_2 = \frac{3.0}{4.0}~sin~30^{\circ}$ $sin~\theta_2 = 0.375$ $\theta_2 = sin^{-1}~(0.375)$ $\theta_2 = 22.0^{\circ}$
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