Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 35 - Interference - Problems - Page 1079: 87c

Answer

The phase difference is $~~0.80$

Work Step by Step

We can see that the intensity decreases from a maximum value when $L = 0$ to a minimum value of zero when $L= 750~nm$ The intensity will fluctuate between maximum value and zero as $L$ increases by $750~nm$ The intensity $I$ is a maximum when $L = 1500~nm$ The phase difference is $1.0~\lambda$ when $L = 1500~nm$ We can find the phase difference $x$ when $L = 1200~nm$: $\frac{1200~nm}{1500~nm} = \frac{x}{1.0~\lambda}$ $x = 0.80~\lambda$ The phase difference is $~~0.80$
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