Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 35 - Interference - Problems - Page 1079: 85

Answer

The angular separation when immersed in water is $~~0.23^{\circ}$

Work Step by Step

We can write an expression for the angular separation in radians: $\Delta \theta = \frac{\lambda}{d}$ When the arrangement is immersed in water, the new wavelength is $\frac{\lambda}{1.33}$ We can see that $\Delta \theta \propto \frac{1}{n}$, where $n$ is the index of refraction We can find the angular separation (in units of degrees) when immersed in water: $\Delta \theta = \frac{0.30^{\circ}}{1.33} = 0.23^{\circ}$ The angular separation when immersed in water is $~~0.23^{\circ}$
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