Answer
$0.2\mu m$
Work Step by Step
We know that:
$dsin{\theta}=m\lambda$
We plug in the known values to obtain:
$dsin(90)=4\times (400\times 10^{-9})=1.6\times 10^{-6}=1.6\mu m$
Now, the change is:
$1.8\mu m -1.6\mu m=0.2\mu m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 35 - Interference - Problems - Page 1075: 26c
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